Base | Representation |
---|---|
bin | 11111001010010111111… |
… | …101101011000110010101 |
3 | 21120201102212020221021020 |
4 | 133022113331223012111 |
5 | 240041133432142331 |
6 | 4315433200311353 |
7 | 310466650132116 |
oct | 37122775530625 |
9 | 7521385227236 |
10 | 2141443240341 |
11 | 7561a9977839 |
12 | 2a7039012559 |
13 | 126c25134522 |
14 | 75909a4820d |
15 | 3aa85785c96 |
hex | 1f297f6b195 |
2141443240341 has 4 divisors (see below), whose sum is σ = 2855257653792. Its totient is φ = 1427628826892.
The previous prime is 2141443240291. The next prime is 2141443240369. The reversal of 2141443240341 is 1430423441412.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2141443240341 - 210 = 2141443239317 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2141443240381) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 356907206721 + ... + 356907206726.
It is an arithmetic number, because the mean of its divisors is an integer number (713814413448).
Almost surely, 22141443240341 is an apocalyptic number.
It is an amenable number.
2141443240341 is a deficient number, since it is larger than the sum of its proper divisors (713814413451).
2141443240341 is an equidigital number, since it uses as much as digits as its factorization.
2141443240341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 713814413450.
The product of its (nonzero) digits is 36864, while the sum is 33.
Adding to 2141443240341 its reverse (1430423441412), we get a palindrome (3571866681753).
The spelling of 2141443240341 in words is "two trillion, one hundred forty-one billion, four hundred forty-three million, two hundred forty thousand, three hundred forty-one".
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