Base | Representation |
---|---|
bin | 11111001010010111111… |
… | …110010100100110011011 |
3 | 21120201102212120120110011 |
4 | 133022113332110212123 |
5 | 240041134003112311 |
6 | 4315433204102351 |
7 | 310466651440531 |
oct | 37122776244633 |
9 | 7521385516404 |
10 | 2141443410331 |
11 | 7561a9a83525 |
12 | 2a70390949b7 |
13 | 126c25193a04 |
14 | 75909a90151 |
15 | 3aa857bb321 |
hex | 1f297f9499b |
2141443410331 has 2 divisors, whose sum is σ = 2141443410332. Its totient is φ = 2141443410330.
The previous prime is 2141443410317. The next prime is 2141443410389. The reversal of 2141443410331 is 1330143441412.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2141443410331 - 237 = 2004004456859 is a prime.
It is a super-2 number, since 2×21414434103312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2141443410293 and 2141443410302.
It is not a weakly prime, because it can be changed into another prime (141443410331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070721705165 + 1070721705166.
It is an arithmetic number, because the mean of its divisors is an integer number (1070721705166).
Almost surely, 22141443410331 is an apocalyptic number.
2141443410331 is a deficient number, since it is larger than the sum of its proper divisors (1).
2141443410331 is an equidigital number, since it uses as much as digits as its factorization.
2141443410331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 2141443410331 its reverse (1330143441412), we get a palindrome (3471586851743).
The spelling of 2141443410331 in words is "two trillion, one hundred forty-one billion, four hundred forty-three million, four hundred ten thousand, three hundred thirty-one".
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