Base | Representation |
---|---|
bin | 1100011110000000100… |
… | …1111101010001010011 |
3 | 202110220221121222202011 |
4 | 3013200021331101103 |
5 | 12002202302313042 |
6 | 242224131403351 |
7 | 21322265561611 |
oct | 3074011752123 |
9 | 673827558664 |
10 | 214214104147 |
11 | 8293630600a |
12 | 35623a53557 |
13 | 1727b0b2ca4 |
14 | a521bac6b1 |
15 | 588b29aa17 |
hex | 31e027d453 |
214214104147 has 2 divisors, whose sum is σ = 214214104148. Its totient is φ = 214214104146.
The previous prime is 214214104079. The next prime is 214214104193. The reversal of 214214104147 is 741401412412.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-214214104147 is a prime.
It is not a weakly prime, because it can be changed into another prime (214214164147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107107052073 + 107107052074.
It is an arithmetic number, because the mean of its divisors is an integer number (107107052074).
Almost surely, 2214214104147 is an apocalyptic number.
214214104147 is a deficient number, since it is larger than the sum of its proper divisors (1).
214214104147 is an equidigital number, since it uses as much as digits as its factorization.
214214104147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7168, while the sum is 31.
Adding to 214214104147 its reverse (741401412412), we get a palindrome (955615516559).
The spelling of 214214104147 in words is "two hundred fourteen billion, two hundred fourteen million, one hundred four thousand, one hundred forty-seven".
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