Base | Representation |
---|---|
bin | 1100011110000101011… |
… | …1011000111000011101 |
3 | 202110222100211020121211 |
4 | 3013201113120320131 |
5 | 12002223001333313 |
6 | 242230134424421 |
7 | 21322633242160 |
oct | 3074127307035 |
9 | 673870736554 |
10 | 214234402333 |
11 | 8294680a376 |
12 | 3562a802111 |
13 | 1728236c053 |
14 | a524773ad7 |
15 | 588ce59e3d |
hex | 31e15d8e1d |
214234402333 has 4 divisors (see below), whose sum is σ = 244839316960. Its totient is φ = 183629487708.
The previous prime is 214234402303. The next prime is 214234402367. The reversal of 214234402333 is 333204432412.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 214234402333 - 213 = 214234394141 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 214234402295 and 214234402304.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (214234402303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15302457303 + ... + 15302457316.
It is an arithmetic number, because the mean of its divisors is an integer number (61209829240).
Almost surely, 2214234402333 is an apocalyptic number.
It is an amenable number.
214234402333 is a deficient number, since it is larger than the sum of its proper divisors (30604914627).
214234402333 is an equidigital number, since it uses as much as digits as its factorization.
214234402333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30604914626.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 214234402333 its reverse (333204432412), we get a palindrome (547438834745).
The spelling of 214234402333 in words is "two hundred fourteen billion, two hundred thirty-four million, four hundred two thousand, three hundred thirty-three".
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