Base | Representation |
---|---|
bin | 1100011110000111000… |
… | …1010101000001001011 |
3 | 202110222211121201100122 |
4 | 3013201301111001023 |
5 | 12002231221433001 |
6 | 242230540253455 |
7 | 21323045113046 |
oct | 3074161250113 |
9 | 673884551318 |
10 | 214241202251 |
11 | 8294a63423a |
12 | 35630b4128b |
13 | 172838b017b |
14 | a525623c5d |
15 | 588d84eb1b |
hex | 31e1c5504b |
214241202251 has 2 divisors, whose sum is σ = 214241202252. Its totient is φ = 214241202250.
The previous prime is 214241202239. The next prime is 214241202281. The reversal of 214241202251 is 152202142412.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-214241202251 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 214241202251.
It is not a weakly prime, because it can be changed into another prime (214241202281) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107120601125 + 107120601126.
It is an arithmetic number, because the mean of its divisors is an integer number (107120601126).
Almost surely, 2214241202251 is an apocalyptic number.
214241202251 is a deficient number, since it is larger than the sum of its proper divisors (1).
214241202251 is an equidigital number, since it uses as much as digits as its factorization.
214241202251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2560, while the sum is 26.
Adding to 214241202251 its reverse (152202142412), we get a palindrome (366443344663).
The spelling of 214241202251 in words is "two hundred fourteen billion, two hundred forty-one million, two hundred two thousand, two hundred fifty-one".
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