Base | Representation |
---|---|
bin | 1100011110011010100… |
… | …1110010011000111001 |
3 | 202111012112202010200211 |
4 | 3013212221302120321 |
5 | 12002413204031411 |
6 | 242243024031121 |
7 | 21325061250343 |
oct | 3074651623071 |
9 | 674175663624 |
10 | 214323111481 |
11 | 82991899916 |
12 | 356544624a1 |
13 | 1729785b57b |
14 | a532466293 |
15 | 5895b2e221 |
hex | 31e6a72639 |
214323111481 has 2 divisors, whose sum is σ = 214323111482. Its totient is φ = 214323111480.
The previous prime is 214323111407. The next prime is 214323111521. The reversal of 214323111481 is 184111323412.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 108333797881 + 105989313600 = 329141^2 + 325560^2 .
It is a cyclic number.
It is not a de Polignac number, because 214323111481 - 221 = 214321014329 is a prime.
It is a super-2 number, since 2×2143231114812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (214323181481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107161555740 + 107161555741.
It is an arithmetic number, because the mean of its divisors is an integer number (107161555741).
Almost surely, 2214323111481 is an apocalyptic number.
It is an amenable number.
214323111481 is a deficient number, since it is larger than the sum of its proper divisors (1).
214323111481 is an equidigital number, since it uses as much as digits as its factorization.
214323111481 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4608, while the sum is 31.
Adding to 214323111481 its reverse (184111323412), we get a palindrome (398434434893).
The spelling of 214323111481 in words is "two hundred fourteen billion, three hundred twenty-three million, one hundred eleven thousand, four hundred eighty-one".
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