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214335001 is a prime number
BaseRepresentation
bin11001100011001…
…11111000011001
3112221022100100101
430301213320121
5414332210001
633133535401
75211550246
oct1461477031
9487270311
10214335001
11aaa94071
125b944561
133553605a
14206745cd
1513c3ba01
hexcc67e19

214335001 has 2 divisors, whose sum is σ = 214335002. Its totient is φ = 214335000.

The previous prime is 214334959. The next prime is 214335019. The reversal of 214335001 is 100533412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 167055625 + 47279376 = 12925^2 + 6876^2 .

It is a cyclic number.

It is not a de Polignac number, because 214335001 - 215 = 214302233 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 214335001.

It is not a weakly prime, because it can be changed into another prime (214335101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107167500 + 107167501.

It is an arithmetic number, because the mean of its divisors is an integer number (107167501).

Almost surely, 2214335001 is an apocalyptic number.

It is an amenable number.

214335001 is a deficient number, since it is larger than the sum of its proper divisors (1).

214335001 is an equidigital number, since it uses as much as digits as its factorization.

214335001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 360, while the sum is 19.

The square root of 214335001 is about 14640.1844592205. The cubic root of 214335001 is about 598.4543559859.

Adding to 214335001 its reverse (100533412), we get a palindrome (314868413).

The spelling of 214335001 in words is "two hundred fourteen million, three hundred thirty-five thousand, one".