Base | Representation |
---|---|
bin | 11111001100110011011… |
… | …011011011111101011011 |
3 | 21120222011122011211011002 |
4 | 133030303123123331123 |
5 | 240112004141324011 |
6 | 4320544052455215 |
7 | 310621411101125 |
oct | 37146333337533 |
9 | 7528148154132 |
10 | 2144051511131 |
11 | 757318201232 |
12 | 2a764661a50b |
13 | 12724c611c1a |
14 | 75ab6200215 |
15 | 3ab8974bc3b |
hex | 1f3336dbf5b |
2144051511131 has 2 divisors, whose sum is σ = 2144051511132. Its totient is φ = 2144051511130.
The previous prime is 2144051511127. The next prime is 2144051511149. The reversal of 2144051511131 is 1311151504412.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2144051511131 - 22 = 2144051511127 is a prime.
It is a super-2 number, since 2×21440515111312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2144051511094 and 2144051511103.
It is not a weakly prime, because it can be changed into another prime (2144051511181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1072025755565 + 1072025755566.
It is an arithmetic number, because the mean of its divisors is an integer number (1072025755566).
Almost surely, 22144051511131 is an apocalyptic number.
2144051511131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2144051511131 is an equidigital number, since it uses as much as digits as its factorization.
2144051511131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2400, while the sum is 29.
The spelling of 2144051511131 in words is "two trillion, one hundred forty-four billion, fifty-one million, five hundred eleven thousand, one hundred thirty-one".
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