Base | Representation |
---|---|
bin | 11111001100110110111… |
… | …110100011111001011111 |
3 | 21120222022210012201120210 |
4 | 133030312332203321133 |
5 | 240112114412102320 |
6 | 4320554020543503 |
7 | 310623033135612 |
oct | 37146676437137 |
9 | 7528283181523 |
10 | 2144111050335 |
11 | 757348877991 |
12 | 2a7662551b93 |
13 | 12725ba5a217 |
14 | 75ac009c179 |
15 | 3ab8eaad0e0 |
hex | 1f336fa3e5f |
2144111050335 has 8 divisors (see below), whose sum is σ = 3430577680560. Its totient is φ = 1143525893504.
The previous prime is 2144111050309. The next prime is 2144111050343. The reversal of 2144111050335 is 5330501114412.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2144111050335 - 28 = 2144111050079 is a prime.
It is a super-2 number, since 2×21441110503352 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 71470368330 + ... + 71470368359.
It is an arithmetic number, because the mean of its divisors is an integer number (428822210070).
Almost surely, 22144111050335 is an apocalyptic number.
2144111050335 is a deficient number, since it is larger than the sum of its proper divisors (1286466630225).
2144111050335 is a wasteful number, since it uses less digits than its factorization.
2144111050335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 142940736697.
The product of its (nonzero) digits is 7200, while the sum is 30.
Adding to 2144111050335 its reverse (5330501114412), we get a palindrome (7474612164747).
The spelling of 2144111050335 in words is "two trillion, one hundred forty-four billion, one hundred eleven million, fifty thousand, three hundred thirty-five".
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