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21441214433 is a prime number
BaseRepresentation
bin10011111101111111…
…101111011111100001
32001100021102112210002
4103331333233133201
5322402422330213
613503331345345
71356222213152
oct237577573741
961307375702
1021441214433
119103008831
1241a4752255
132039156942
141075885929
15857552658
hex4fdfef7e1

21441214433 has 2 divisors, whose sum is σ = 21441214434. Its totient is φ = 21441214432.

The previous prime is 21441214393. The next prime is 21441214439. The reversal of 21441214433 is 33441214412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20640494224 + 800720209 = 143668^2 + 28297^2 .

It is a cyclic number.

It is not a de Polignac number, because 21441214433 - 212 = 21441210337 is a prime.

It is a super-2 number, since 2×214412144332 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21441214396 and 21441214405.

It is not a weakly prime, because it can be changed into another prime (21441214439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10720607216 + 10720607217.

It is an arithmetic number, because the mean of its divisors is an integer number (10720607217).

Almost surely, 221441214433 is an apocalyptic number.

It is an amenable number.

21441214433 is a deficient number, since it is larger than the sum of its proper divisors (1).

21441214433 is an equidigital number, since it uses as much as digits as its factorization.

21441214433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 9216, while the sum is 29.

Adding to 21441214433 its reverse (33441214412), we get a palindrome (54882428845).

The spelling of 21441214433 in words is "twenty-one billion, four hundred forty-one million, two hundred fourteen thousand, four hundred thirty-three".