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2144141312332 = 222632038157141
BaseRepresentation
bin11111001100111000110…
…010000000000101001100
321120222101220011012020111
4133030320302000011030
5240112200133443312
64321001021325404
7310623551305165
oct37147062000514
97528356135214
102144141312332
117573639671a8
122a7670706864
131272650c4526
1475ac40d876c
153ab925898a7
hex1f338c8014c

2144141312332 has 12 divisors (see below), whose sum is σ = 3766514398416. Its totient is φ = 1067994341360.

The previous prime is 2144141312321. The next prime is 2144141312359. The reversal of 2144141312332 is 2332131414412.

It is a happy number.

It is a junction number, because it is equal to n+sod(n) for n = 2144141312294 and 2144141312303.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1019077519 + ... + 1019079622.

It is an arithmetic number, because the mean of its divisors is an integer number (313876199868).

Almost surely, 22144141312332 is an apocalyptic number.

It is an amenable number.

2144141312332 is a deficient number, since it is larger than the sum of its proper divisors (1622373086084).

2144141312332 is a wasteful number, since it uses less digits than its factorization.

2144141312332 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2038157408 (or 2038157406 counting only the distinct ones).

The product of its digits is 13824, while the sum is 31.

Adding to 2144141312332 its reverse (2332131414412), we get a palindrome (4476272726744).

The spelling of 2144141312332 in words is "two trillion, one hundred forty-four billion, one hundred forty-one million, three hundred twelve thousand, three hundred thirty-two".

Divisors: 1 2 4 263 526 1052 2038157141 4076314282 8152628564 536035328083 1072070656166 2144141312332