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2144240311335 = 35251827688657
BaseRepresentation
bin11111001100111110101…
…011101001110000100111
321120222122210102212100020
4133030332223221300213
5240112401004430320
64321014515250223
7310626162631053
oct37147653516047
97528583385306
102144240311335
11757404834661
122a76998a9973
1312727c777515
1475ad3308c63
153ab9b0e2940
hex1f33eae9c27

2144240311335 has 32 divisors (see below), whose sum is σ = 3448622967552. Its totient is φ = 1137659712000.

The previous prime is 2144240311309. The next prime is 2144240311363. The reversal of 2144240311335 is 5331130424412.

It is not a de Polignac number, because 2144240311335 - 25 = 2144240311303 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2144240311296 and 2144240311305.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2769327 + ... + 3457983.

It is an arithmetic number, because the mean of its divisors is an integer number (107769467736).

Almost surely, 22144240311335 is an apocalyptic number.

2144240311335 is a deficient number, since it is larger than the sum of its proper divisors (1304382656217).

2144240311335 is a wasteful number, since it uses less digits than its factorization.

2144240311335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 689743.

The product of its (nonzero) digits is 34560, while the sum is 33.

Adding to 2144240311335 its reverse (5331130424412), we get a palindrome (7475370735747).

The spelling of 2144240311335 in words is "two trillion, one hundred forty-four billion, two hundred forty million, three hundred eleven thousand, three hundred thirty-five".

Divisors: 1 3 5 15 251 753 827 1255 2481 3765 4135 12405 207577 622731 688657 1037885 2065971 3113655 3443285 10329855 172852907 518558721 569519339 864264535 1708558017 2592793605 2847596695 8542790085 142949354089 428848062267 714746770445 2144240311335