Base | Representation |
---|---|
bin | 11111001100111110101… |
… | …011101001110000100111 |
3 | 21120222122210102212100020 |
4 | 133030332223221300213 |
5 | 240112401004430320 |
6 | 4321014515250223 |
7 | 310626162631053 |
oct | 37147653516047 |
9 | 7528583385306 |
10 | 2144240311335 |
11 | 757404834661 |
12 | 2a76998a9973 |
13 | 12727c777515 |
14 | 75ad3308c63 |
15 | 3ab9b0e2940 |
hex | 1f33eae9c27 |
2144240311335 has 32 divisors (see below), whose sum is σ = 3448622967552. Its totient is φ = 1137659712000.
The previous prime is 2144240311309. The next prime is 2144240311363. The reversal of 2144240311335 is 5331130424412.
It is not a de Polignac number, because 2144240311335 - 25 = 2144240311303 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2144240311296 and 2144240311305.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2769327 + ... + 3457983.
It is an arithmetic number, because the mean of its divisors is an integer number (107769467736).
Almost surely, 22144240311335 is an apocalyptic number.
2144240311335 is a deficient number, since it is larger than the sum of its proper divisors (1304382656217).
2144240311335 is a wasteful number, since it uses less digits than its factorization.
2144240311335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 689743.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 2144240311335 its reverse (5331130424412), we get a palindrome (7475370735747).
The spelling of 2144240311335 in words is "two trillion, one hundred forty-four billion, two hundred forty million, three hundred eleven thousand, three hundred thirty-five".
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