Base | Representation |
---|---|
bin | 1100011110110100001… |
… | …0101110100000100011 |
3 | 202111111000110111211022 |
4 | 3013231002232200203 |
5 | 12003123124444413 |
6 | 242301413440055 |
7 | 21330532403612 |
oct | 3075502564043 |
9 | 674430414738 |
10 | 214430312483 |
11 | 82a37359592 |
12 | 3568434002b |
13 | 172b3b2390a |
14 | a5427ad879 |
15 | 58a0257608 |
hex | 31ed0ae823 |
214430312483 has 2 divisors, whose sum is σ = 214430312484. Its totient is φ = 214430312482.
The previous prime is 214430312389. The next prime is 214430312491. The reversal of 214430312483 is 384213034412.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 214430312483 - 212 = 214430308387 is a prime.
It is not a weakly prime, because it can be changed into another prime (214430312983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107215156241 + 107215156242.
It is an arithmetic number, because the mean of its divisors is an integer number (107215156242).
Almost surely, 2214430312483 is an apocalyptic number.
214430312483 is a deficient number, since it is larger than the sum of its proper divisors (1).
214430312483 is an equidigital number, since it uses as much as digits as its factorization.
214430312483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 214430312483 its reverse (384213034412), we get a palindrome (598643346895).
The spelling of 214430312483 in words is "two hundred fourteen billion, four hundred thirty million, three hundred twelve thousand, four hundred eighty-three".
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