Base | Representation |
---|---|
bin | 1001110000000110100110… |
… | …10101101010001100010111 |
3 | 2210221000202210101112122100 |
4 | 10320003103111222030113 |
5 | 10302314324214141210 |
6 | 113335125313533143 |
7 | 4342164603012405 |
oct | 470032325521427 |
9 | 83830683345570 |
10 | 21444022412055 |
11 | 69183a4675051 |
12 | 24a3bb38741b3 |
13 | bc721640ab29 |
14 | 541c79340475 |
15 | 272c1cbcd5c0 |
hex | 1380d356a317 |
21444022412055 has 48 divisors (see below), whose sum is σ = 37184317069536. Its totient is φ = 11432296730880.
The previous prime is 21444022412023. The next prime is 21444022412077. The reversal of 21444022412055 is 55021422044412.
21444022412055 is a `hidden beast` number, since 2 + 1 + 4 + 4 + 402 + 2 + 41 + 205 + 5 = 666.
It is not a de Polignac number, because 21444022412055 - 25 = 21444022412023 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2192411265 + ... + 2192421045.
It is an arithmetic number, because the mean of its divisors is an integer number (774673272282).
Almost surely, 221444022412055 is an apocalyptic number.
21444022412055 is a deficient number, since it is larger than the sum of its proper divisors (15740294657481).
21444022412055 is a wasteful number, since it uses less digits than its factorization.
21444022412055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24048 (or 24045 counting only the distinct ones).
The product of its (nonzero) digits is 102400, while the sum is 36.
Adding to 21444022412055 its reverse (55021422044412), we get a palindrome (76465444456467).
The spelling of 21444022412055 in words is "twenty-one trillion, four hundred forty-four billion, twenty-two million, four hundred twelve thousand, fifty-five".
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