Base | Representation |
---|---|
bin | 11111001101001010110… |
… | …101100000011110010011 |
3 | 21121000012000010120021022 |
4 | 133031022311200132103 |
5 | 240113310210040311 |
6 | 4321051041550055 |
7 | 310634220061616 |
oct | 37151265403623 |
9 | 7530160116238 |
10 | 2144444221331 |
11 | 7574a9948215 |
12 | 2a773604532b |
13 | 1272b2aa0419 |
14 | 75b1242817d |
15 | 3abade705db |
hex | 1f34ad60793 |
2144444221331 has 2 divisors, whose sum is σ = 2144444221332. Its totient is φ = 2144444221330.
The previous prime is 2144444221261. The next prime is 2144444221357. The reversal of 2144444221331 is 1331224444412.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2144444221331 - 210 = 2144444220307 is a prime.
It is a super-2 number, since 2×21444442213312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2144444221291 and 2144444221300.
It is not a weakly prime, because it can be changed into another prime (2144444271331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1072222110665 + 1072222110666.
It is an arithmetic number, because the mean of its divisors is an integer number (1072222110666).
Almost surely, 22144444221331 is an apocalyptic number.
2144444221331 is a deficient number, since it is larger than the sum of its proper divisors (1).
2144444221331 is an equidigital number, since it uses as much as digits as its factorization.
2144444221331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 73728, while the sum is 35.
Adding to 2144444221331 its reverse (1331224444412), we get a palindrome (3475668665743).
The spelling of 2144444221331 in words is "two trillion, one hundred forty-four billion, four hundred forty-four million, two hundred twenty-one thousand, three hundred thirty-one".
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