Base | Representation |
---|---|
bin | 1001110000010110010001… |
… | …10001101001011111100001 |
3 | 2210221211111002102010012122 |
4 | 10320023020301221133201 |
5 | 10302434041343300213 |
6 | 113343040155434025 |
7 | 4342613224662662 |
oct | 470131061513741 |
9 | 83854432363178 |
10 | 21452435134433 |
11 | 6920a21407976 |
12 | 24a5761155915 |
13 | bc7c572c8274 |
14 | 542436761369 |
15 | 273061551d08 |
hex | 1382c8c697e1 |
21452435134433 has 2 divisors, whose sum is σ = 21452435134434. Its totient is φ = 21452435134432.
The previous prime is 21452435134397. The next prime is 21452435134453. The reversal of 21452435134433 is 33443153425412.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20233515356224 + 1218919778209 = 4498168^2 + 1104047^2 .
It is a cyclic number.
It is not a de Polignac number, because 21452435134433 - 244 = 3860249090017 is a prime.
It is not a weakly prime, because it can be changed into another prime (21452435134453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10726217567216 + 10726217567217.
It is an arithmetic number, because the mean of its divisors is an integer number (10726217567217).
Almost surely, 221452435134433 is an apocalyptic number.
It is an amenable number.
21452435134433 is a deficient number, since it is larger than the sum of its proper divisors (1).
21452435134433 is an equidigital number, since it uses as much as digits as its factorization.
21452435134433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2073600, while the sum is 44.
Adding to 21452435134433 its reverse (33443153425412), we get a palindrome (54895588559845).
The spelling of 21452435134433 in words is "twenty-one trillion, four hundred fifty-two billion, four hundred thirty-five million, one hundred thirty-four thousand, four hundred thirty-three".
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