Base | Representation |
---|---|
bin | 1001110000100110010001… |
… | …01101100100101000010111 |
3 | 2210222122122122212201112120 |
4 | 10320103020231210220113 |
5 | 10303104134121004120 |
6 | 113351020332551023 |
7 | 4343336116100640 |
oct | 470231055445027 |
9 | 83878578781476 |
10 | 21461024000535 |
11 | 6924629619119 |
12 | 24a7359622473 |
13 | bc89c5839262 |
14 | 542a0d3146c7 |
15 | 2733b55bb140 |
hex | 1384c8b64a17 |
21461024000535 has 64 divisors (see below), whose sum is σ = 39315802927104. Its totient is φ = 9792570816000.
The previous prime is 21461024000503. The next prime is 21461024000593. The reversal of 21461024000535 is 53500042016412.
It is not a de Polignac number, because 21461024000535 - 25 = 21461024000503 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21461024000496 and 21461024000505.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 151029970 + ... + 151172000.
It is an arithmetic number, because the mean of its divisors is an integer number (614309420736).
Almost surely, 221461024000535 is an apocalyptic number.
21461024000535 is a deficient number, since it is larger than the sum of its proper divisors (17854778926569).
21461024000535 is a wasteful number, since it uses less digits than its factorization.
21461024000535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 144704.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 21461024000535 its reverse (53500042016412), we get a palindrome (74961066016947).
The spelling of 21461024000535 in words is "twenty-one trillion, four hundred sixty-one billion, twenty-four million, five hundred thirty-five", and thus it is an aban number.
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