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21476570661433 is a prime number
BaseRepresentation
bin1001110001000011001110…
…10111011000001000111001
32211001010210010122221000001
410320201213113120020321
510303333004042131213
6113402111135513001
74344426304403626
oct470414727301071
984033703587001
1021476570661433
1169301872775a8
1224aa378088761
13bca3026c69a4
14543685d9934d
152739c53b41dd
hex1388675d8239

21476570661433 has 2 divisors, whose sum is σ = 21476570661434. Its totient is φ = 21476570661432.

The previous prime is 21476570661421. The next prime is 21476570661443. The reversal of 21476570661433 is 33416607567412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21445123668544 + 31446992889 = 4630888^2 + 177333^2 .

It is a cyclic number.

It is not a de Polignac number, because 21476570661433 - 25 = 21476570661401 is a prime.

It is a super-2 number, since 2×214765706614332 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (21476570661443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10738285330716 + 10738285330717.

It is an arithmetic number, because the mean of its divisors is an integer number (10738285330717).

Almost surely, 221476570661433 is an apocalyptic number.

It is an amenable number.

21476570661433 is a deficient number, since it is larger than the sum of its proper divisors (1).

21476570661433 is an equidigital number, since it uses as much as digits as its factorization.

21476570661433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15240960, while the sum is 55.

The spelling of 21476570661433 in words is "twenty-one trillion, four hundred seventy-six billion, five hundred seventy million, six hundred sixty-one thousand, four hundred thirty-three".