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2148143452993 is a prime number
BaseRepresentation
bin11111010000100111010…
…100111101001101000001
321121100201210220000010101
4133100213110331031001
5240143344210443433
64322502105202401
7311124666035566
oct37204724751501
97540653800111
102148143452993
11759027a8276a
122a83a8a90401
131277522b53b5
1475d8384886d
153ad28ad407d
hex1f42753d341

2148143452993 has 2 divisors, whose sum is σ = 2148143452994. Its totient is φ = 2148143452992.

The previous prime is 2148143452963. The next prime is 2148143452999. The reversal of 2148143452993 is 3992543418412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1680113700864 + 468029752129 = 1296192^2 + 684127^2 .

It is a cyclic number.

It is not a de Polignac number, because 2148143452993 - 213 = 2148143444801 is a prime.

It is a super-2 number, since 2×21481434529932 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2148143452999) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1074071726496 + 1074071726497.

It is an arithmetic number, because the mean of its divisors is an integer number (1074071726497).

Almost surely, 22148143452993 is an apocalyptic number.

It is an amenable number.

2148143452993 is a deficient number, since it is larger than the sum of its proper divisors (1).

2148143452993 is an equidigital number, since it uses as much as digits as its factorization.

2148143452993 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7464960, while the sum is 55.

The spelling of 2148143452993 in words is "two trillion, one hundred forty-eight billion, one hundred forty-three million, four hundred fifty-two thousand, nine hundred ninety-three".