Base | Representation |
---|---|
bin | 11111010001001001101… |
… | …010110111000011110011 |
3 | 21121102012222001100010201 |
4 | 133101021222313003303 |
5 | 240201034210322324 |
6 | 4323035210340031 |
7 | 311145163264015 |
oct | 37211152670363 |
9 | 7542188040121 |
10 | 2148719620339 |
11 | 7592a3232826 |
12 | 2a8529a2a617 |
13 | 127814788216 |
14 | 75dda18a1b5 |
15 | 3ad5e495444 |
hex | 1f449ab70f3 |
2148719620339 has 2 divisors, whose sum is σ = 2148719620340. Its totient is φ = 2148719620338.
The previous prime is 2148719620303. The next prime is 2148719620367. The reversal of 2148719620339 is 9330269178412.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2148719620339 - 27 = 2148719620211 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2148719620339.
It is not a weakly prime, because it can be changed into another prime (2148719629339) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1074359810169 + 1074359810170.
It is an arithmetic number, because the mean of its divisors is an integer number (1074359810170).
Almost surely, 22148719620339 is an apocalyptic number.
2148719620339 is a deficient number, since it is larger than the sum of its proper divisors (1).
2148719620339 is an equidigital number, since it uses as much as digits as its factorization.
2148719620339 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3919104, while the sum is 55.
The spelling of 2148719620339 in words is "two trillion, one hundred forty-eight billion, seven hundred nineteen million, six hundred twenty thousand, three hundred thirty-nine".
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