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214922903 = 1316532531
BaseRepresentation
bin11001100111101…
…11011010010111
3112222102012210112
430303313122113
5420010013103
633154313235
75216546246
oct1463673227
9488365715
10214922903
11100355838
125bb8881b
13356b0820
142078895d
1513d05cd8
hexccf7697

214922903 has 4 divisors (see below), whose sum is σ = 231455448. Its totient is φ = 198390360.

The previous prime is 214922887. The next prime is 214922909. The reversal of 214922903 is 309229412.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 214922903 - 24 = 214922887 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 214922903.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (214922909) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8266253 + ... + 8266278.

It is an arithmetic number, because the mean of its divisors is an integer number (57863862).

Almost surely, 2214922903 is an apocalyptic number.

214922903 is a deficient number, since it is larger than the sum of its proper divisors (16532545).

214922903 is a wasteful number, since it uses less digits than its factorization.

214922903 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16532544.

The product of its (nonzero) digits is 7776, while the sum is 32.

The square root of 214922903 is about 14660.2490770109. The cubic root of 214922903 is about 599.0010256364.

It can be divided in two parts, 2149 and 22903, that added together give a palindrome (25052).

The spelling of 214922903 in words is "two hundred fourteen million, nine hundred twenty-two thousand, nine hundred three".

Divisors: 1 13 16532531 214922903