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214936433 is a prime number
BaseRepresentation
bin11001100111110…
…10101101110001
3112222102220100122
430303322231301
5420010431213
633154500025
75216633555
oct1463725561
9488386318
10214936433
11100364a18
125bb94615
13356b6a2a
142078d865
1513d09d08
hexccfab71

214936433 has 2 divisors, whose sum is σ = 214936434. Its totient is φ = 214936432.

The previous prime is 214936387. The next prime is 214936459. The reversal of 214936433 is 334639412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 201157489 + 13778944 = 14183^2 + 3712^2 .

It is a cyclic number.

It is not a de Polignac number, because 214936433 - 212 = 214932337 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 214936393 and 214936402.

It is not a weakly prime, because it can be changed into another prime (214936133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107468216 + 107468217.

It is an arithmetic number, because the mean of its divisors is an integer number (107468217).

Almost surely, 2214936433 is an apocalyptic number.

It is an amenable number.

214936433 is a deficient number, since it is larger than the sum of its proper divisors (1).

214936433 is an equidigital number, since it uses as much as digits as its factorization.

214936433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 46656, while the sum is 35.

The square root of 214936433 is about 14660.7105216630. The cubic root of 214936433 is about 599.0135949713.

The spelling of 214936433 in words is "two hundred fourteen million, nine hundred thirty-six thousand, four hundred thirty-three".