Base | Representation |
---|---|
bin | 1001110001101111110100… |
… | …11111111110110111100111 |
3 | 2211010102120210021202221100 |
4 | 10320313322133332313213 |
5 | 10304231023041120310 |
6 | 113421111052451143 |
7 | 4346234531432463 |
oct | 470677237766747 |
9 | 84112523252840 |
10 | 21500514004455 |
11 | 693a3537025a2 |
12 | 24b2b3a779ab3 |
13 | bcc64a046895 |
14 | 5448b7c874a3 |
15 | 274427412ec0 |
hex | 138dfa7fede7 |
21500514004455 has 48 divisors (see below), whose sum is σ = 37364782740480. Its totient is φ = 11437040721600.
The previous prime is 21500514004451. The next prime is 21500514004457. The reversal of 21500514004455 is 55440041500512.
21500514004455 is a `hidden beast` number, since 2 + 1 + 50 + 0 + 514 + 0 + 0 + 44 + 55 = 666.
It is not a de Polignac number, because 21500514004455 - 22 = 21500514004451 is a prime.
It is a super-3 number, since 3×215005140044553 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21500514004451) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 67937976 + ... + 68253714.
It is an arithmetic number, because the mean of its divisors is an integer number (778432973760).
Almost surely, 221500514004455 is an apocalyptic number.
21500514004455 is a deficient number, since it is larger than the sum of its proper divisors (15864268736025).
21500514004455 is a wasteful number, since it uses less digits than its factorization.
21500514004455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 319692 (or 319689 counting only the distinct ones).
The product of its (nonzero) digits is 80000, while the sum is 36.
Adding to 21500514004455 its reverse (55440041500512), we get a palindrome (76940555504967).
The spelling of 21500514004455 in words is "twenty-one trillion, five hundred billion, five hundred fourteen million, four thousand, four hundred fifty-five".
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