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2150130252045 = 35143342016803
BaseRepresentation
bin11111010010011101101…
…111111111100100001101
321121112212021101212001110
4133102131233333210031
5240211431321031140
64323431201202233
7311225142406626
oct37223557774415
97545767355043
102150130252045
11759957523256
122a8862330379
131279aaab9c39
14760d1668a4d
153ade323a380
hex1f49dbff90d

2150130252045 has 8 divisors (see below), whose sum is σ = 3440208403296. Its totient is φ = 1146736134416.

The previous prime is 2150130251959. The next prime is 2150130252097. The reversal of 2150130252045 is 5402520310512.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2150130252045 - 222 = 2150126057741 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 71671008387 + ... + 71671008416.

It is an arithmetic number, because the mean of its divisors is an integer number (430026050412).

Almost surely, 22150130252045 is an apocalyptic number.

It is an amenable number.

2150130252045 is a deficient number, since it is larger than the sum of its proper divisors (1290078151251).

2150130252045 is a wasteful number, since it uses less digits than its factorization.

2150130252045 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 143342016811.

The product of its (nonzero) digits is 12000, while the sum is 30.

Adding to 2150130252045 its reverse (5402520310512), we get a palindrome (7552650562557).

The spelling of 2150130252045 in words is "two trillion, one hundred fifty billion, one hundred thirty million, two hundred fifty-two thousand, forty-five".

Divisors: 1 3 5 15 143342016803 430026050409 716710084015 2150130252045