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2150213415335 = 5430042683067
BaseRepresentation
bin11111010010100010101…
…101001111000110100111
321121120002001212222122022
4133102202231033012213
5240212114113242320
64323443331453355
7311230202316326
oct37224255170647
97546061788568
102150213415335
1175999a465047
122a888615725b
131279c20b709b
14760dc7160bd
153adea6b6325
hex1f4a2b4f1a7

2150213415335 has 4 divisors (see below), whose sum is σ = 2580256098408. Its totient is φ = 1720170732264.

The previous prime is 2150213415289. The next prime is 2150213415347. The reversal of 2150213415335 is 5335143120512.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2150213415335 - 26 = 2150213415271 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2150213415295 and 2150213415304.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 215021341529 + ... + 215021341538.

It is an arithmetic number, because the mean of its divisors is an integer number (645064024602).

Almost surely, 22150213415335 is an apocalyptic number.

2150213415335 is a deficient number, since it is larger than the sum of its proper divisors (430042683073).

2150213415335 is an equidigital number, since it uses as much as digits as its factorization.

2150213415335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 430042683072.

The product of its (nonzero) digits is 54000, while the sum is 35.

Adding to 2150213415335 its reverse (5335143120512), we get a palindrome (7485356535847).

The spelling of 2150213415335 in words is "two trillion, one hundred fifty billion, two hundred thirteen million, four hundred fifteen thousand, three hundred thirty-five".

Divisors: 1 5 430042683067 2150213415335