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215043940661761 is a prime number
BaseRepresentation
bin110000111001010011010001…
…101100011011101000000001
31001012101222222222002100000001
4300321103101230123220001
5211141234442302134021
62041205453400000001
763203261214132001
oct6071232154335001
91035358888070001
10215043940661761
1162579694357422
1220150b58760001
1392cb730aa7923
143b1627a1b2001
1519cdbbe13e091
hexc394d1b1ba01

215043940661761 has 2 divisors, whose sum is σ = 215043940661762. Its totient is φ = 215043940661760.

The previous prime is 215043940661651. The next prime is 215043940661773. The reversal of 215043940661761 is 167166049340512.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 184277394164161 + 30766546497600 = 13574881^2 + 5546760^2 .

It is a cyclic number.

It is not a de Polignac number, because 215043940661761 - 243 = 206247847639553 is a prime.

It is a super-2 number, since 2×2150439406617612 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (215043940061761) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107521970330880 + 107521970330881.

It is an arithmetic number, because the mean of its divisors is an integer number (107521970330881).

Almost surely, 2215043940661761 is an apocalyptic number.

It is an amenable number.

215043940661761 is a deficient number, since it is larger than the sum of its proper divisors (1).

215043940661761 is an equidigital number, since it uses as much as digits as its factorization.

215043940661761 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6531840, while the sum is 55.

The spelling of 215043940661761 in words is "two hundred fifteen trillion, forty-three billion, nine hundred forty million, six hundred sixty-one thousand, seven hundred sixty-one".