Base | Representation |
---|---|
bin | 1100100001001000101… |
… | …0100110011000011101 |
3 | 202120002102102002102111 |
4 | 3020102022212120131 |
5 | 12010412100231331 |
6 | 242443302554021 |
7 | 21352134321064 |
oct | 3102212463035 |
9 | 676072362374 |
10 | 215053133341 |
11 | 83226984072 |
12 | 35818a38911 |
13 | 17382b7c877 |
14 | a5a13b71db |
15 | 58d9c81db1 |
hex | 32122a661d |
215053133341 has 4 divisors (see below), whose sum is σ = 218082050784. Its totient is φ = 212024215900.
The previous prime is 215053133333. The next prime is 215053133371. The reversal of 215053133341 is 143331350512.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 215053133341 - 23 = 215053133333 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (215053133311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1514458615 + ... + 1514458756.
It is an arithmetic number, because the mean of its divisors is an integer number (54520512696).
Almost surely, 2215053133341 is an apocalyptic number.
It is an amenable number.
215053133341 is a deficient number, since it is larger than the sum of its proper divisors (3028917443).
215053133341 is an equidigital number, since it uses as much as digits as its factorization.
215053133341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3028917442.
The product of its (nonzero) digits is 16200, while the sum is 31.
Adding to 215053133341 its reverse (143331350512), we get a palindrome (358384483853).
The spelling of 215053133341 in words is "two hundred fifteen billion, fifty-three million, one hundred thirty-three thousand, three hundred forty-one".
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