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215054525141497 is a prime number
BaseRepresentation
bin110000111001011101001000…
…100101000001000111111001
31001012110000022121122121121001
4300321131020211001013321
5211141423131414011442
62041214403542045001
763204114416542336
oct6071351045010771
91035400277577531
10215054525141497
1162583125a89738
1220153011419761
1392cc7298b85a2
143b169a1bdb98d
1519ce0dd4a12b7
hexc397489411f9

215054525141497 has 2 divisors, whose sum is σ = 215054525141498. Its totient is φ = 215054525141496.

The previous prime is 215054525141429. The next prime is 215054525141557. The reversal of 215054525141497 is 794141525450512.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 207145668213136 + 7908856928361 = 14392556^2 + 2812269^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-215054525141497 is a prime.

It is not a weakly prime, because it can be changed into another prime (215054525148497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107527262570748 + 107527262570749.

It is an arithmetic number, because the mean of its divisors is an integer number (107527262570749).

Almost surely, 2215054525141497 is an apocalyptic number.

It is an amenable number.

215054525141497 is a deficient number, since it is larger than the sum of its proper divisors (1).

215054525141497 is an equidigital number, since it uses as much as digits as its factorization.

215054525141497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10080000, while the sum is 55.

The spelling of 215054525141497 in words is "two hundred fifteen trillion, fifty-four billion, five hundred twenty-five million, one hundred forty-one thousand, four hundred ninety-seven".