Base | Representation |
---|---|
bin | 1001110001111100110001… |
… | …00001010001011101000111 |
3 | 2211011002111212121111122021 |
4 | 10320332120201101131013 |
5 | 10304334234242011101 |
6 | 113424220223544011 |
7 | 4346601624364501 |
oct | 470763041213507 |
9 | 84132455544567 |
10 | 21507460110151 |
11 | 6942298596614 |
12 | 24b4358a5b007 |
13 | c001b612c9b2 |
14 | 544d765b4d71 |
15 | 2746d21335a1 |
hex | 138f98851747 |
21507460110151 has 4 divisors (see below), whose sum is σ = 21507598816704. Its totient is φ = 21507321403600.
The previous prime is 21507460110077. The next prime is 21507460110179. The reversal of 21507460110151 is 15101106470512.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 21507460110151 - 27 = 21507460110023 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21507460110551) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69120430 + ... + 69430891.
It is an arithmetic number, because the mean of its divisors is an integer number (5376899704176).
Almost surely, 221507460110151 is an apocalyptic number.
21507460110151 is a deficient number, since it is larger than the sum of its proper divisors (138706553).
21507460110151 is a wasteful number, since it uses less digits than its factorization.
21507460110151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 138706552.
The product of its (nonzero) digits is 8400, while the sum is 34.
Adding to 21507460110151 its reverse (15101106470512), we get a palindrome (36608566580663).
The spelling of 21507460110151 in words is "twenty-one trillion, five hundred seven billion, four hundred sixty million, one hundred ten thousand, one hundred fifty-one".
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