Base | Representation |
---|---|
bin | 11111010011011110010… |
… | …100010011100110101111 |
3 | 21121122122202202012220120 |
4 | 133103132110103212233 |
5 | 240221141124410020 |
6 | 4324130455220023 |
7 | 311264035105341 |
oct | 37233624234657 |
9 | 7548582665816 |
10 | 2151213513135 |
11 | 75a362a45355 |
12 | 2a8b05077613 |
13 | 127b2135992b |
14 | 7619548b291 |
15 | 3ae583b6740 |
hex | 1f4de5139af |
2151213513135 has 32 divisors (see below), whose sum is σ = 3568667120640. Its totient is φ = 1105250659968.
The previous prime is 2151213513089. The next prime is 2151213513161. The reversal of 2151213513135 is 5313153121512.
It is not a de Polignac number, because 2151213513135 - 210 = 2151213512111 is a prime.
It is a super-3 number, since 3×21512135131353 (a number of 38 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2151213513096 and 2151213513105.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5388919 + ... + 5774328.
It is an arithmetic number, because the mean of its divisors is an integer number (111520847520).
Almost surely, 22151213513135 is an apocalyptic number.
2151213513135 is a deficient number, since it is larger than the sum of its proper divisors (1417453607505).
2151213513135 is a wasteful number, since it uses less digits than its factorization.
2151213513135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11163727.
The product of its digits is 13500, while the sum is 33.
Adding to 2151213513135 its reverse (5313153121512), we get a palindrome (7464366634647).
The spelling of 2151213513135 in words is "two trillion, one hundred fifty-one billion, two hundred thirteen million, five hundred thirteen thousand, one hundred thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •