Base | Representation |
---|---|
bin | 11111010011100000000… |
… | …010100101010100101011 |
3 | 21121122201210010220210111 |
4 | 133103200002211110223 |
5 | 240221221024442142 |
6 | 4324133410555151 |
7 | 311264535606412 |
oct | 37234002452453 |
9 | 7548653126714 |
10 | 2151242421547 |
11 | 75a37829a6aa |
12 | 2a8b12898ab7 |
13 | 127b2733babb |
14 | 76199254479 |
15 | 3ae5abc6e17 |
hex | 1f4e00a552b |
2151242421547 has 2 divisors, whose sum is σ = 2151242421548. Its totient is φ = 2151242421546.
The previous prime is 2151242421421. The next prime is 2151242421551. The reversal of 2151242421547 is 7451242421512.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2151242421547 is a prime.
It is not a weakly prime, because it can be changed into another prime (2151242421247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075621210773 + 1075621210774.
It is an arithmetic number, because the mean of its divisors is an integer number (1075621210774).
Almost surely, 22151242421547 is an apocalyptic number.
2151242421547 is a deficient number, since it is larger than the sum of its proper divisors (1).
2151242421547 is an equidigital number, since it uses as much as digits as its factorization.
2151242421547 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 179200, while the sum is 40.
The spelling of 2151242421547 in words is "two trillion, one hundred fifty-one billion, two hundred forty-two million, four hundred twenty-one thousand, five hundred forty-seven".
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