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215125142207 = 2111019550437
BaseRepresentation
bin1100100001011001110…
…1010010101010111111
3202120021102220112000112
43020112131102222333
512011034014022312
6242454354220235
721354000352343
oct3102635225277
9676242815015
10215125142207
1183263597428
1235838b8467b
1317394a72871
14a5aab9d623
1558e1257d22
hex3216752abf

215125142207 has 4 divisors (see below), whose sum is σ = 216144692856. Its totient is φ = 214105591560.

The previous prime is 215125142201. The next prime is 215125142257. The reversal of 215125142207 is 702241521512.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 215125142207 - 216 = 215125076671 is a prime.

It is a super-3 number, since 3×2151251422073 (a number of 35 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (215125142201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 509775008 + ... + 509775429.

It is an arithmetic number, because the mean of its divisors is an integer number (54036173214).

Almost surely, 2215125142207 is an apocalyptic number.

215125142207 is a deficient number, since it is larger than the sum of its proper divisors (1019550649).

215125142207 is a wasteful number, since it uses less digits than its factorization.

215125142207 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1019550648.

The product of its (nonzero) digits is 11200, while the sum is 32.

Adding to 215125142207 its reverse (702241521512), we get a palindrome (917366663719).

The spelling of 215125142207 in words is "two hundred fifteen billion, one hundred twenty-five million, one hundred forty-two thousand, two hundred seven".

Divisors: 1 211 1019550437 215125142207