Base | Representation |
---|---|
bin | 1100100001011011000… |
… | …0010001111101110111 |
3 | 202120021210021102100021 |
4 | 3020112300101331313 |
5 | 12011041302320210 |
6 | 242455053030011 |
7 | 21354060564124 |
oct | 3102660217567 |
9 | 676253242307 |
10 | 215130120055 |
11 | 83266387354 |
12 | 3583a785307 |
13 | 17395ac6536 |
14 | a5ab6d774b |
15 | 58e18dcbda |
hex | 3216c11f77 |
215130120055 has 4 divisors (see below), whose sum is σ = 258156144072. Its totient is φ = 172104096040.
The previous prime is 215130120013. The next prime is 215130120097. The reversal of 215130120055 is 550021031512.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (215130120013) and next prime (215130120097).
It is not a de Polignac number, because 215130120055 - 213 = 215130111863 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21513012001 + ... + 21513012010.
It is an arithmetic number, because the mean of its divisors is an integer number (64539036018).
Almost surely, 2215130120055 is an apocalyptic number.
215130120055 is a deficient number, since it is larger than the sum of its proper divisors (43026024017).
215130120055 is an equidigital number, since it uses as much as digits as its factorization.
215130120055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43026024016.
The product of its (nonzero) digits is 1500, while the sum is 25.
Adding to 215130120055 its reverse (550021031512), we get a palindrome (765151151567).
The spelling of 215130120055 in words is "two hundred fifteen billion, one hundred thirty million, one hundred twenty thousand, fifty-five".
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