Base | Representation |
---|---|
bin | 11111010011100101110… |
… | …111000001100111100110 |
3 | 21121122222120212012201211 |
4 | 133103211313001213212 |
5 | 240221421023230024 |
6 | 4324151215342034 |
7 | 311300132514163 |
oct | 37234567014746 |
9 | 7548876765654 |
10 | 2151340055014 |
11 | 75a418415117 |
12 | 2a8b3b52191a |
13 | 127b41634397 |
14 | 761a81cb06a |
15 | 3ae64560594 |
hex | 1f4e5dc19e6 |
2151340055014 has 4 divisors (see below), whose sum is σ = 3227010082524. Its totient is φ = 1075670027506.
The previous prime is 2151340054987. The next prime is 2151340055027. The reversal of 2151340055014 is 4105500431512.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 537835013752 + ... + 537835013755.
It is an arithmetic number, because the mean of its divisors is an integer number (806752520631).
Almost surely, 22151340055014 is an apocalyptic number.
2151340055014 is a deficient number, since it is larger than the sum of its proper divisors (1075670027510).
2151340055014 is a wasteful number, since it uses less digits than its factorization.
2151340055014 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1075670027509.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 2151340055014 its reverse (4105500431512), we get a palindrome (6256840486526).
The spelling of 2151340055014 in words is "two trillion, one hundred fifty-one billion, three hundred forty million, fifty-five thousand, fourteen".
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