Base | Representation |
---|---|
bin | 1001110010001000000101… |
… | …11011011111010110011001 |
3 | 2211011200012121121221010020 |
4 | 10321010002323133112121 |
5 | 10304434212311210001 |
6 | 113431103424141053 |
7 | 4350205404423531 |
oct | 471040273372631 |
9 | 84150177557106 |
10 | 21513540335001 |
11 | 6944928731530 |
12 | 24b5575167789 |
13 | c00944a07290 |
14 | 545391d084c1 |
15 | 27493ad16736 |
hex | 139102edf599 |
21513540335001 has 64 divisors (see below), whose sum is σ = 35474572277760. Its totient is φ = 11401653312000.
The previous prime is 21513540334991. The next prime is 21513540335117. The reversal of 21513540335001 is 10053304531512.
It is not a de Polignac number, because 21513540335001 - 213 = 21513540326809 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is not an unprimeable number, because it can be changed into a prime (21513540335401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 415927821 + ... + 415979541.
It is an arithmetic number, because the mean of its divisors is an integer number (554290191840).
Almost surely, 221513540335001 is an apocalyptic number.
It is an amenable number.
21513540335001 is a deficient number, since it is larger than the sum of its proper divisors (13961031942759).
21513540335001 is a wasteful number, since it uses less digits than its factorization.
21513540335001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 102798.
The product of its (nonzero) digits is 27000, while the sum is 33.
Adding to 21513540335001 its reverse (10053304531512), we get a palindrome (31566844866513).
The spelling of 21513540335001 in words is "twenty-one trillion, five hundred thirteen billion, five hundred forty million, three hundred thirty-five thousand, one".
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