Base | Representation |
---|---|
bin | 11111010011100110110… |
… | …000000101100110100111 |
3 | 21121200000122000011222102 |
4 | 133103212300011212213 |
5 | 240221433340413133 |
6 | 4324152512122315 |
7 | 311300403615101 |
oct | 37234660054647 |
9 | 7550018004872 |
10 | 2151355013543 |
11 | 75a42590173a |
12 | 2a8b4453639b |
13 | 127b44770b98 |
14 | 761aa1a2571 |
15 | 3ae65a177e8 |
hex | 1f4e6c059a7 |
2151355013543 has 4 divisors (see below), whose sum is σ = 2152072374000. Its totient is φ = 2150637653088.
The previous prime is 2151355013471. The next prime is 2151355013573. The reversal of 2151355013543 is 3453105531512.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2151355013543 - 216 = 2151354948007 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2151355013497 and 2151355013506.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2151355013573) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 358675730 + ... + 358681727.
It is an arithmetic number, because the mean of its divisors is an integer number (538018093500).
Almost surely, 22151355013543 is an apocalyptic number.
2151355013543 is a deficient number, since it is larger than the sum of its proper divisors (717360457).
2151355013543 is an equidigital number, since it uses as much as digits as its factorization.
2151355013543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 717360456.
The product of its (nonzero) digits is 135000, while the sum is 38.
The spelling of 2151355013543 in words is "two trillion, one hundred fifty-one billion, three hundred fifty-five million, thirteen thousand, five hundred forty-three".
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