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2151404011 is a prime number
BaseRepresentation
bin1000000000111011…
…1101000111101011
312112221020122111001
42000032331013223
513401224412021
6553252015431
7104212426621
oct20016750753
95487218431
102151404011
11a04458749
12500601577
13283948333
14165a2b511
15c8d1d091
hex803bd1eb

2151404011 has 2 divisors, whose sum is σ = 2151404012. Its totient is φ = 2151404010.

The previous prime is 2151403987. The next prime is 2151404033. The reversal of 2151404011 is 1104041512.

2151404011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2151404011 - 25 = 2151403979 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2151404011.

It is not a weakly prime, because it can be changed into another prime (2151404051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075702005 + 1075702006.

It is an arithmetic number, because the mean of its divisors is an integer number (1075702006).

Almost surely, 22151404011 is an apocalyptic number.

2151404011 is a deficient number, since it is larger than the sum of its proper divisors (1).

2151404011 is an equidigital number, since it uses as much as digits as its factorization.

2151404011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 160, while the sum is 19.

The square root of 2151404011 is about 46383.2298465728. The cubic root of 2151404011 is about 1290.9437660342.

Adding to 2151404011 its reverse (1104041512), we get a palindrome (3255445523).

The spelling of 2151404011 in words is "two billion, one hundred fifty-one million, four hundred four thousand, eleven".