Base | Representation |
---|---|
bin | 1001110010001001100110… |
… | …11000011010100101001011 |
3 | 2211011202022021012222012121 |
4 | 10321010303120122211023 |
5 | 10304442343411132021 |
6 | 113431320223152111 |
7 | 4350234505031404 |
oct | 471046330324513 |
9 | 84152267188177 |
10 | 21514353224011 |
11 | 694520557602a |
12 | 24b5761445637 |
13 | c00a442509ab |
14 | 54542bc6a9ab |
15 | 274987387741 |
hex | 13913361a94b |
21514353224011 has 4 divisors (see below), whose sum is σ = 21540368162232. Its totient is φ = 21488338285792.
The previous prime is 21514353223969. The next prime is 21514353224051. The reversal of 21514353224011 is 11042235341512.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 21514353224011 - 213 = 21514353215819 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (21514353224051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13007467870 + ... + 13007469523.
It is an arithmetic number, because the mean of its divisors is an integer number (5385092040558).
Almost surely, 221514353224011 is an apocalyptic number.
21514353224011 is a deficient number, since it is larger than the sum of its proper divisors (26014938221).
21514353224011 is an equidigital number, since it uses as much as digits as its factorization.
21514353224011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26014938220.
The product of its (nonzero) digits is 28800, while the sum is 34.
Adding to 21514353224011 its reverse (11042235341512), we get a palindrome (32556588565523).
The spelling of 21514353224011 in words is "twenty-one trillion, five hundred fourteen billion, three hundred fifty-three million, two hundred twenty-four thousand, eleven".
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