Base | Representation |
---|---|
bin | 1001110010001001100110… |
… | …11000011010100101110011 |
3 | 2211011202022021012222021002 |
4 | 10321010303120122211303 |
5 | 10304442343411132201 |
6 | 113431320223152215 |
7 | 4350234505031462 |
oct | 471046330324563 |
9 | 84152267188232 |
10 | 21514353224051 |
11 | 6945205576066 |
12 | 24b576144566b |
13 | c00a44250a0c |
14 | 54542bc6a9d9 |
15 | 27498738776b |
hex | 13913361a973 |
21514353224051 has 2 divisors, whose sum is σ = 21514353224052. Its totient is φ = 21514353224050.
The previous prime is 21514353223969. The next prime is 21514353224059. The reversal of 21514353224051 is 15042235341512.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21514353224051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21514353223996 and 21514353224014.
It is not a weakly prime, because it can be changed into another prime (21514353224059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10757176612025 + 10757176612026.
It is an arithmetic number, because the mean of its divisors is an integer number (10757176612026).
Almost surely, 221514353224051 is an apocalyptic number.
21514353224051 is a deficient number, since it is larger than the sum of its proper divisors (1).
21514353224051 is an equidigital number, since it uses as much as digits as its factorization.
21514353224051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144000, while the sum is 38.
Adding to 21514353224051 its reverse (15042235341512), we get a palindrome (36556588565563).
The spelling of 21514353224051 in words is "twenty-one trillion, five hundred fourteen billion, three hundred fifty-three million, two hundred twenty-four thousand, fifty-one".
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