Base | Representation |
---|---|
bin | 1001110010001010110100… |
… | …01011001000011011111011 |
3 | 2211011210222121212112001222 |
4 | 10321011122023020123323 |
5 | 10310000212014200433 |
6 | 113431504552502255 |
7 | 4350256600010621 |
oct | 471053213103373 |
9 | 84153877775058 |
10 | 21515004053243 |
11 | 6945509990728 |
12 | 24b59033aa98b |
13 | c00b1903524c |
14 | 545490485511 |
15 | 2749c4595b98 |
hex | 13915a2c86fb |
21515004053243 has 2 divisors, whose sum is σ = 21515004053244. Its totient is φ = 21515004053242.
The previous prime is 21515004053107. The next prime is 21515004053447. The reversal of 21515004053243 is 34235040051512.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21515004053243 - 28 = 21515004052987 is a prime.
It is a super-2 number, since 2×215150040532432 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21515004073243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10757502026621 + 10757502026622.
It is an arithmetic number, because the mean of its divisors is an integer number (10757502026622).
Almost surely, 221515004053243 is an apocalyptic number.
21515004053243 is a deficient number, since it is larger than the sum of its proper divisors (1).
21515004053243 is an equidigital number, since it uses as much as digits as its factorization.
21515004053243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72000, while the sum is 35.
The spelling of 21515004053243 in words is "twenty-one trillion, five hundred fifteen billion, four million, fifty-three thousand, two hundred forty-three".
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