Base | Representation |
---|---|
bin | 110000111010111000011010… |
… | …101110100000000111010011 |
3 | 1001012210101022110010121012111 |
4 | 300322320122232200013103 |
5 | 211200024400232423403 |
6 | 2041331413515210151 |
7 | 63214154341255555 |
oct | 6072703256400723 |
9 | 1035711273117174 |
10 | 215152540123603 |
11 | 62610752980485 |
12 | 2016a006446957 |
13 | 9308a4a098114 |
14 | 3b1b61d3834d5 |
15 | 19d19282d756d |
hex | c3ae1aba01d3 |
215152540123603 has 2 divisors, whose sum is σ = 215152540123604. Its totient is φ = 215152540123602.
The previous prime is 215152540123513. The next prime is 215152540123607. The reversal of 215152540123603 is 306321045251512.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 215152540123603 - 213 = 215152540115411 is a prime.
It is not a weakly prime, because it can be changed into another prime (215152540123607) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107576270061801 + 107576270061802.
It is an arithmetic number, because the mean of its divisors is an integer number (107576270061802).
Almost surely, 2215152540123603 is an apocalyptic number.
215152540123603 is a deficient number, since it is larger than the sum of its proper divisors (1).
215152540123603 is an equidigital number, since it uses as much as digits as its factorization.
215152540123603 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216000, while the sum is 40.
The spelling of 215152540123603 in words is "two hundred fifteen trillion, one hundred fifty-two billion, five hundred forty million, one hundred twenty-three thousand, six hundred three".
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