Search a number
-
+
2152003142857 is a prime number
BaseRepresentation
bin11111010100001101011…
…000100000010011001001
321121201200210120120020211
4133110031120200103021
5240224300301032412
64324341103521121
7311322433620661
oct37241530402311
97551623516224
102152003142857
1175a7287428a7
122a90a55b91a1
13127c18b1b559
147622c2b71a1
153aea2890ca7
hex1f50d6204c9

2152003142857 has 2 divisors, whose sum is σ = 2152003142858. Its totient is φ = 2152003142856.

The previous prime is 2152003142819. The next prime is 2152003142869. The reversal of 2152003142857 is 7582413002512.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1301358474441 + 850644668416 = 1140771^2 + 922304^2 .

It is a cyclic number.

It is not a de Polignac number, because 2152003142857 - 211 = 2152003140809 is a prime.

It is a super-2 number, since 2×21520031428572 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2152003142657) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1076001571428 + 1076001571429.

It is an arithmetic number, because the mean of its divisors is an integer number (1076001571429).

Almost surely, 22152003142857 is an apocalyptic number.

It is an amenable number.

2152003142857 is a deficient number, since it is larger than the sum of its proper divisors (1).

2152003142857 is an equidigital number, since it uses as much as digits as its factorization.

2152003142857 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 134400, while the sum is 40.

The spelling of 2152003142857 in words is "two trillion, one hundred fifty-two billion, three million, one hundred forty-two thousand, eight hundred fifty-seven".