Base | Representation |
---|---|
bin | 11111010100010011111… |
… | …011110100100000000001 |
3 | 21121201222110102010121221 |
4 | 133110103323310200001 |
5 | 240230011421021222 |
6 | 4324400031515041 |
7 | 311325240133414 |
oct | 37242373644001 |
9 | 7551873363557 |
10 | 2152113063937 |
11 | 75a7847a0171 |
12 | 2a9116388a81 |
13 | 127c35826a05 |
14 | 7623cb2bb7b |
15 | 3aeac3550c7 |
hex | 1f513ef4801 |
2152113063937 has 2 divisors, whose sum is σ = 2152113063938. Its totient is φ = 2152113063936.
The previous prime is 2152113063929. The next prime is 2152113063941. The reversal of 2152113063937 is 7393603112512.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1656474535681 + 495638528256 = 1287041^2 + 704016^2 .
It is a cyclic number.
It is not a de Polignac number, because 2152113063937 - 23 = 2152113063929 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2152113063893 and 2152113063902.
It is not a weakly prime, because it can be changed into another prime (2152113069937) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1076056531968 + 1076056531969.
It is an arithmetic number, because the mean of its divisors is an integer number (1076056531969).
Almost surely, 22152113063937 is an apocalyptic number.
It is an amenable number.
2152113063937 is a deficient number, since it is larger than the sum of its proper divisors (1).
2152113063937 is an equidigital number, since it uses as much as digits as its factorization.
2152113063937 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 204120, while the sum is 43.
The spelling of 2152113063937 in words is "two trillion, one hundred fifty-two billion, one hundred thirteen million, sixty-three thousand, nine hundred thirty-seven".
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