Base | Representation |
---|---|
bin | 1100100001101110110… |
… | …1110010010001101101 |
3 | 202120111120220001011120 |
4 | 3020123231302101231 |
5 | 12011224104231140 |
6 | 242511225011153 |
7 | 21356121211026 |
oct | 3103355622155 |
9 | 676446801146 |
10 | 215213352045 |
11 | 832a936581a |
12 | 35862623ab9 |
13 | 173aa118a33 |
14 | a5b87a1c4d |
15 | 58e8d7e1d0 |
hex | 321bb7246d |
215213352045 has 32 divisors (see below), whose sum is σ = 355542635520. Its totient is φ = 111048645120.
The previous prime is 215213352043. The next prime is 215213352091. The reversal of 215213352045 is 540253312512.
It is not a de Polignac number, because 215213352045 - 21 = 215213352043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 215213351997 and 215213352015.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (215213352043) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1768087 + ... + 1885883.
It is an arithmetic number, because the mean of its divisors is an integer number (11110707360).
Almost surely, 2215213352045 is an apocalyptic number.
It is an amenable number.
215213352045 is a deficient number, since it is larger than the sum of its proper divisors (140329283475).
215213352045 is a wasteful number, since it uses less digits than its factorization.
215213352045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 121765.
The product of its (nonzero) digits is 36000, while the sum is 33.
Adding to 215213352045 its reverse (540253312512), we get a palindrome (755466664557).
The spelling of 215213352045 in words is "two hundred fifteen billion, two hundred thirteen million, three hundred fifty-two thousand, forty-five".
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