Base | Representation |
---|---|
bin | 1100100001111000001… |
… | …0110000011101010011 |
3 | 202120121022101002110011 |
4 | 3020132002300131103 |
5 | 12011314103412201 |
6 | 242515142015351 |
7 | 21360104150206 |
oct | 3103602603523 |
9 | 676538332404 |
10 | 215252404051 |
11 | 83319409103 |
12 | 35873717557 |
13 | 173b523cc29 |
14 | a5bda4993d |
15 | 58ec4e5151 |
hex | 321e0b0753 |
215252404051 has 2 divisors, whose sum is σ = 215252404052. Its totient is φ = 215252404050.
The previous prime is 215252404033. The next prime is 215252404067. The reversal of 215252404051 is 150404252512.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 215252404051 - 215 = 215252371283 is a prime.
It is a super-2 number, since 2×2152524040512 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (215252401051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107626202025 + 107626202026.
It is an arithmetic number, because the mean of its divisors is an integer number (107626202026).
Almost surely, 2215252404051 is an apocalyptic number.
215252404051 is a deficient number, since it is larger than the sum of its proper divisors (1).
215252404051 is an equidigital number, since it uses as much as digits as its factorization.
215252404051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16000, while the sum is 31.
Adding to 215252404051 its reverse (150404252512), we get a palindrome (365656656563).
The spelling of 215252404051 in words is "two hundred fifteen billion, two hundred fifty-two million, four hundred four thousand, fifty-one".
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