Base | Representation |
---|---|
bin | 11111010101001111011… |
… | …111101100110000000001 |
3 | 21121211120002200212021102 |
4 | 133111033133230300001 |
5 | 240234033223400441 |
6 | 4325043125304145 |
7 | 311362062536342 |
oct | 37251737546001 |
9 | 7554502625242 |
10 | 2153112325121 |
11 | 76014785995a |
12 | 2a9354b65055 |
13 | 128064865814 |
14 | 762d57260c9 |
15 | 3b019e3c69b |
hex | 1f54f7ecc01 |
2153112325121 has 2 divisors, whose sum is σ = 2153112325122. Its totient is φ = 2153112325120.
The previous prime is 2153112325087. The next prime is 2153112325153. The reversal of 2153112325121 is 1215232113512.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1449770116096 + 703342209025 = 1204064^2 + 838655^2 .
It is a cyclic number.
It is not a de Polignac number, because 2153112325121 - 230 = 2152038583297 is a prime.
It is not a weakly prime, because it can be changed into another prime (2153112525121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1076556162560 + 1076556162561.
It is an arithmetic number, because the mean of its divisors is an integer number (1076556162561).
Almost surely, 22153112325121 is an apocalyptic number.
It is an amenable number.
2153112325121 is a deficient number, since it is larger than the sum of its proper divisors (1).
2153112325121 is an equidigital number, since it uses as much as digits as its factorization.
2153112325121 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3600, while the sum is 29.
Adding to 2153112325121 its reverse (1215232113512), we get a palindrome (3368344438633).
The spelling of 2153112325121 in words is "two trillion, one hundred fifty-three billion, one hundred twelve million, three hundred twenty-five thousand, one hundred twenty-one".
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