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2153151673301 = 19113323772279
BaseRepresentation
bin11111010101010001110…
…101110011001111010101
321121211122211201221211102
4133111101311303033111
5240234123312021201
64325051052515445
7311363051151146
oct37252165631725
97554584657742
102153151673301
11760167a94812
122a936617bb85
1312806ca61775
14762daa49acd
153b01d61126b
hex1f551d733d5

2153151673301 has 4 divisors (see below), whose sum is σ = 2266475445600. Its totient is φ = 2039827901004.

The previous prime is 2153151673249. The next prime is 2153151673303. The reversal of 2153151673301 is 1033761513512.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2153151673301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2153151673303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56661886121 + ... + 56661886158.

It is an arithmetic number, because the mean of its divisors is an integer number (566618861400).

Almost surely, 22153151673301 is an apocalyptic number.

It is an amenable number.

2153151673301 is a deficient number, since it is larger than the sum of its proper divisors (113323772299).

2153151673301 is a wasteful number, since it uses less digits than its factorization.

2153151673301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 113323772298.

The product of its (nonzero) digits is 56700, while the sum is 38.

The spelling of 2153151673301 in words is "two trillion, one hundred fifty-three billion, one hundred fifty-one million, six hundred seventy-three thousand, three hundred one".

Divisors: 1 19 113323772279 2153151673301