Base | Representation |
---|---|
bin | 11111010101011010101… |
… | …001111010111011100011 |
3 | 21121212001011000002001001 |
4 | 133111122221322323203 |
5 | 240234424141212034 |
6 | 4325113454252431 |
7 | 311366525133235 |
oct | 37253251727343 |
9 | 7555034002031 |
10 | 2153299554019 |
11 | 760233509789 |
12 | 2a93a77b7117 |
13 | 12809459ab53 |
14 | 76312542255 |
15 | 3b02b5c2a14 |
hex | 1f55aa7aee3 |
2153299554019 has 2 divisors, whose sum is σ = 2153299554020. Its totient is φ = 2153299554018.
The previous prime is 2153299553983. The next prime is 2153299554103. The reversal of 2153299554019 is 9104559923512.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2153299554019 - 221 = 2153297456867 is a prime.
It is a super-2 number, since 2×21532995540192 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2153299554919) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1076649777009 + 1076649777010.
It is an arithmetic number, because the mean of its divisors is an integer number (1076649777010).
Almost surely, 22153299554019 is an apocalyptic number.
2153299554019 is a deficient number, since it is larger than the sum of its proper divisors (1).
2153299554019 is an equidigital number, since it uses as much as digits as its factorization.
2153299554019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4374000, while the sum is 55.
The spelling of 2153299554019 in words is "two trillion, one hundred fifty-three billion, two hundred ninety-nine million, five hundred fifty-four thousand, nineteen".
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