Base | Representation |
---|---|
bin | 11111010101011101101… |
… | …010011011110001000011 |
3 | 21121212011122222000120111 |
4 | 133111131222123301003 |
5 | 240240030101121123 |
6 | 4325122500052151 |
7 | 311401010111656 |
oct | 37253552336103 |
9 | 7555148860514 |
10 | 2153350020163 |
11 | 760259a48741 |
12 | 2a9400694057 |
13 | 1280a1b8a484 |
14 | 7631911b89d |
15 | 3b030c4090d |
hex | 1f55da9bc43 |
2153350020163 has 2 divisors, whose sum is σ = 2153350020164. Its totient is φ = 2153350020162.
The previous prime is 2153350020013. The next prime is 2153350020169. The reversal of 2153350020163 is 3610200533512.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2153350020163 is a prime.
It is not a weakly prime, because it can be changed into another prime (2153350020169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1076675010081 + 1076675010082.
It is an arithmetic number, because the mean of its divisors is an integer number (1076675010082).
Almost surely, 22153350020163 is an apocalyptic number.
2153350020163 is a deficient number, since it is larger than the sum of its proper divisors (1).
2153350020163 is an equidigital number, since it uses as much as digits as its factorization.
2153350020163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16200, while the sum is 31.
Adding to 2153350020163 its reverse (3610200533512), we get a palindrome (5763550553675).
The spelling of 2153350020163 in words is "two trillion, one hundred fifty-three billion, three hundred fifty million, twenty thousand, one hundred sixty-three".
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