Base | Representation |
---|---|
bin | 1001110010101101010110… |
… | …00100100011100100111011 |
3 | 2211020120211111200202120022 |
4 | 10321112223010203210323 |
5 | 10310301143013344313 |
6 | 113444212223121055 |
7 | 4351514136525521 |
oct | 471265304434473 |
9 | 84216744622508 |
10 | 21533541153083 |
11 | 695236166a153 |
12 | 24b941744318b |
13 | c027b160a38b |
14 | 54632c364311 |
15 | 27520bb94c08 |
hex | 1395ab12393b |
21533541153083 has 2 divisors, whose sum is σ = 21533541153084. Its totient is φ = 21533541153082.
The previous prime is 21533541152957. The next prime is 21533541153101. The reversal of 21533541153083 is 38035114533512.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21533541153083 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (21533541183083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10766770576541 + 10766770576542.
It is an arithmetic number, because the mean of its divisors is an integer number (10766770576542).
Almost surely, 221533541153083 is an apocalyptic number.
21533541153083 is a deficient number, since it is larger than the sum of its proper divisors (1).
21533541153083 is an equidigital number, since it uses as much as digits as its factorization.
21533541153083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648000, while the sum is 44.
Adding to 21533541153083 its reverse (38035114533512), we get a palindrome (59568655686595).
The spelling of 21533541153083 in words is "twenty-one trillion, five hundred thirty-three billion, five hundred forty-one million, one hundred fifty-three thousand, eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •